将对象数组与字符串数组进行比较并删除重复项

Question

I have been searching for quite some time, but cannot find the solution.

I have an array of objects -

const arrayOfObjects = [{id:"EUR", name:"EURO"}, {id:"USD", name:"US Dollar"}...]

and then I have an array of strings

const arrayOfStrings = ["EUR"]

I want to get a third array, which will contain complete objects, but only the ones where id!== an element in arrayOfStrings.

So the result -

const resultArray = [{id:"USD", name:"US Dollar"}].

How would I go about that?

EDIT: I am doing this as part of a createSelector

export const currencies = curr => {
  return createSelector(
    [arrayObjectSelector, arrayStringsSelector(curr)],
    (objectArr, stringArr) =>
      objectArr &&
      objectArr.filter(
        currency => stringArr && stringArr.indexOf(currency.id) == -1
      )
  );
};

For some reason, the currencies array remains unchanged..

Answer 1

You could filter the array using Array#filter with non-exist id value of arrayOfStrings

 const arrayOfObjects = [{id:"EUR", name:"EURO"}, {id:"USD", name:"US Dollar"}] const arrayOfStrings = ["EUR"] const res = arrayOfObjects.filter(item=> arrayOfStrings.indexOf(item.id) == -1); console.log(res)