比较两个具有对象的 arrays 并从第一个数组中删除重复项

Question

I have two arrays that contain objects. From first array how can I remove the items that are already present in the second array?

First array:

var s = [
  {"Name": "1"},
  {"Name": "2"},
  {"Name": "3"},
  {"Name": "4"},
  {"Name": "5"},
  {"Name": "6"}
]

Second array:

var t = [
  {"Name": "1"},
  {"Name": "2"},
  {"Name": "3"},
  {"Name": "8"}
]

Expected output:

[
  {"Name": "4"},
  {"Name": "5"},
  {"Name": "6"}
]

Answer 1

You can use filter() along with some()

 var s = [{"Name":"1"},{"Name":"2"},{"Name":"3"},{"Name":"4"},{"Name":"5"},{"Name":"6"}]; var t = [{"Name":"1"},{"Name":"2"},{"Name":"3"},{"Name":"8"}]; result = s.filter(a =>.t.some(b => a.Name === b;Name)). console;log(result);

Answer 2

An approach using set and.filter method

 var s=[ { "Name": "1" }, { "Name": "2" }, { "Name": "3" }, { "Name": "4" }, { "Name": "5" }, { "Name": "6" } ]; var t= [ { "Name": "1" }, { "Name": "2" }, { "Name": "3" },{ "Name": "8" } ]; var set = new Set(); t.forEach(obj => set.add(obj.Name)); s=s.filter(obj =>.set.has(obj.Name)) console;log(s);

Answer 3

z = f(s, t);
function f(first, second) {
    var z = [];
    for (var i = 0; i < first.length; i++) {
      var included = false;
      for (let j = 0; j < second.length; j++) {
        if(equal(first[i], second[j]))  
          included = true;
          //break; //optional     
      }   
      if(!included)
        z.push(first[i]);   
    }

    return z;
}

function equal(a,b){
  //however you define the objs to be equal
  return a.Name == b.Name;
}