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如何将存储在向量中的变量值分配给 R 中存储在字符向量中的一系列变量名称?

[英]How to assign a variable values stored in a vector to a series of variable names stored in a character vector in R?

I am trying to determine how to assign variable a values stored in a vector to a series of variable names stored in a character vector in R?我正在尝试确定如何将存储在向量中的变量值分配给存储在 R 中字符向量中的一系列变量名称?

Here is a toy example of what I'm trying to do: I would like to have ultimately have the values 1, 2, and 3, stored in the variables A, B, and C respectively, so that print(A) returns 1 , print(B ) returns 2 , etc. However, I would like to store the variables A, B, and C as character values in a vector called my_variables .这是我正在尝试做的一个玩具示例:我希望最终将值 1、2 和 3 分别存储在变量 A、B 和 C 中,以便print(A)返回1print(B ) 返回2等。但是,我想将变量A, B, and C作为字符值存储在名为 my_variables 的向量中。 So:所以:

my_variables <-c("A", "B", "C")

and I have the values 1, 2, 3, stored in a vector called my_values:我将值 1、2、3 存储在名为 my_values 的向量中:

my_values <-1:3

I tried to use this, but it didn't quite work the way I wanted:我尝试使用它,但它并没有像我想要的那样工作:

   assign(my_variables, my_values)

This simply assigns "A" "B" "C" to the variable my_variables, but nothing is assigned to the variable A .这只是将"A" "B" "C"分配给变量 my_variables,但没有分配给变量A

I can accomplish what I want to do with an array, but I wonder if there is a more efficient way to do this with vectorized operations?我可以用数组完成我想做的事情,但我想知道是否有更有效的方法来使用矢量化操作来做到这一点? Is there a better way to approach this than using a loop?有没有比使用循环更好的方法来解决这个问题?

assign is not vectorized, so you can use Map here specifying the environment. assign未矢量化,因此您可以在此处使用Map指定环境。

Map(function(x, y) assign(x, y, envir = .GlobalEnv), my_variables, my_values)

A
#[1] 1
B
#[1] 2
C
#[1] 3

However, it is not a good practice to have such variables in the global environment.但是,在全局环境中使用此类变量并不是一个好习惯。

Use a named vector :使用命名向量:

name_vec <- setNames(my_values, my_variables)
name_vec
#A B C 
#1 2 3 

Or named list as.list(name_vec) .或命名列表as.list(name_vec)

This will do the trick这将解决问题

val = 1:3
var = LETTERS[1:3]

l = as.list(val)
names(l) = var
list2env(l, envir = environment())

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