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Zend_db和Zend_paginator-玩得很开心

[英]Zend_db & Zend_paginator - Not having a fun time

I am having a serious problem converting my 'select' statement into something that will work with the zend paginator... could someone have a crack at it, as I am having no luck... 我遇到了一个严重的问题,即将我的“ select”语句转换为可以与zend paginator一起使用的内容...可能有人对此有所破解,因为我没有运气...

Here is my query: 这是我的查询:

$query = "SELECT
            user_id, name, gender, city, province, country, image_id, one_liner, self_description, reputation
          FROM
            users
          WHERE
          (
            (69.1 * (latitude - " . $user->latitude . ")) * 
            (69.1 * (latitude - " . $user->latitude . "))
          ) + ( 
            (69.1 * (longitude - " . $user->longitude . ") * COS(" . $user->latitude . " / 57.3)) * 
            (69.1 * (longitude - " . $user->longitude . ") * COS(" . $user->latitude . " / 57.3))
          ) < " . pow($radius, 2) . " 
          ORDER BY 
          (
                (69.1 * (latitude - " . $user->latitude . ")) * 
            (69.1 * (latitude - " . $user->latitude . "))
          ) + ( 
            (69.1 * (longitude - " . $user->longitude . ") * COS(" . $user->latitude . " / 57.3)) * 
            (69.1 * (longitude - " . $user->longitude . ") * COS(" . $user->latitude . " / 57.3))

Here is what I have so far: 这是我到目前为止的内容:

        $select = $db->select();
        $select->from(
            array('users'),
                array(
                        'user_id', 
                        'name', 
                        'gender', 
                        'city', 
                        'province', 
                        'country', 
                        'image_id', 
                        'one_liner', 
                        'self_description', 
                        'reputation'
                    )
        );
        $select->where("(69.1 * (latitude - " . $user->latitude . ")) * (69.1 * (latitude - " . $user->latitude . "))) + ((69.1 * (longitude - " . $user->longitude . ") * COS(" . $user->latitude . " / 57.3)) * (69.1 * (longitude - " . $user->longitude . ") * COS(" . $user->latitude . " / 57.3))) < " . pow($radius, 2));
        $select->order("(69.1 * (latitude - " . $user->latitude . ")) * (69.1 * (latitude - " . $user->latitude . "))) + ((69.1 * (longitude - " . $user->longitude . ") * COS(" . $user->latitude . " / 57.3)) * (69.1 * (longitude - " . $user->longitude . ") * COS(" . $user->latitude . " / 57.3))) ASC");

为什么在order by子句中有“ <”?

What does this have to do with Zend_Paginator? 这与Zend_Paginator有什么关系? Ah, do you have the query and you don't know how to make a paginator with it, or is the paginator not working with this query? 啊,您是否有查询,并且您不知道如何使用它进行分页,或者分页器无法与此查询一起使用?

The only thing I can see is you're missing an opening parenthesis in both the where() and order() clause: 我唯一能看到的是,您在where()order()子句中都缺少左括号:

$select->where("((69.1 * [...] ");
$select->order("((69.1 * [...] ");
                 ^

So maybe Zend_Paginator isn't working because the SQL query has errors? 那么也许Zend_Paginator不能正常工作,因为SQL查询有错误吗?

And of course I have to ask: are those variables you're interpolating safe, or should you really be using $db->quote($user->latitude, Zend_Db::FLOAT_TYPE) ? 当然,我不得不问:您插值的那些变量是安全的,还是真的应该使用$db->quote($user->latitude, Zend_Db::FLOAT_TYPE)

Assuming you are using MVC-pattern, won't this work? 假设您使用的是MVC模式,这行不通吗?

in your bootstrap: 在您的引导程序中:

Zend_View_Helper_PaginationControl::setDefaultViewPartial('pagination.phtml');

in your controller: 在您的控制器中:

$page = Zend_Paginator::factory($select);
$page->setCurrentPageNumber($this->_getParam('page', 1));
$page->setItemCountPerPage($this->_getParam('par', 20));
$this->view->results= $page;

in your view: 在您看来:

<?php foreach($this->results as $result) : ?>
    <!-- print some $result stuff here -->
<?php endforeach;?>
<?= $this->results ?>

then place a pagination.phtml example that you can find on zend manual -Lo 然后将一个pagination.phtml示例放在zend manual -Lo上

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