python中函数编码的问题：Base 2 & 10 integer palindrome

Question

There was a question which asked to write a code, to get continuous integer input from user until a negative integer is input and for each input I should evaluate if it is a palindrome in both base 10 and 2. If yes then print 'Yes' else print 'No'.

For example: 99 = (1100011)base2, both versions are palindrome so it prints 'Yes'

This is a usual elementary method.

while 1:
    num = int(input('Input: '))
    if num > 0:
        num1 = str(num)
        if num1 == num1[::-1]:
            list1 = list(bin(num))
            list1.pop(0)
            list1.pop(0)
            n = ''.join(list1)
            if n == n[::-1]:
                print('Yes')
            else:
                print('No')
        else:
            print('No')
    else:
        break

But when I tried to type a code using defining a new function it didn't work well. Here following is the code. Can you note what is wrong with this.

def palindrome(n):
    n = str(n)
    if n == n[::-1]:
        return True
    else:
        return False


def b2_palindrome(n):
    list1 = list(bin(n))
    list1.pop(0)
    list1.pop(0)
    n = ''.join(list1)
    palindrome(n)


while 1:
    num = int(input('Input: '))
    if num > 0:
        if b2_palindrome(num) and palindrome(num):
            print('Yes')
        else:
            print('No')
    else:
        break

@dspencer: edited the indentations

Answer 1

you're not returning the value of the palindrome call in b2_palindrome

see below:

def b2_palindrome(n):
    list1 = list(bin(n))
    list1.pop(0)
    list1.pop(0)
    n = ''.join(list1)
    return palindrome(n)  # <-- added return here