除了 Python 之外，在 try 中存储并继续执行

Question

I want to store the error message and continue the execution but when I store the error message using the except exception e: then I am not able to continue the execution. The function stops execution if URL does not get the HTTP URL, the function gives an error if

url="www.boomlive.in/fact-file/did-the-race-to-5g-cause-the-coronavirus-outbreak-7404"

My code is

def twitter_link(url):
    twitter_title=[]
    response = requests.get(url)
    soup = BeautifulSoup(response.text, "html.parser")
    for i in soup.find_all("p"):
        try:
           for a in i.find_all("a", href=True):
              if "twitter" in a["href"]:
                 x=a["href"]
               twitter_title.append(x)
        except Exception as e:
           twitter_title.append(str(e))
           continue  

    return twitter_title

My excepted output is function stores URL in list twitter_title, if there is an error then store the error message and continue the executions

Answer 1

The function stops executing because the exception is thrown by requests.get(url) and that call is not inside the try-block.