包括 function 遍历 javascript 中的所有数组

Question

I have a code which iterates over an array of Objects and checks if it contains admin word.If it contains then I want to call Admin API and if not then I want to call Non-Admin API. The code works fine however the issue is while iterating it say authority contains 5 Objects and 3rd index contains admin keyword then the logic calls 2 non-admin api and 1 admin api and then again 2 non-admin apis. Is there a better way to write the code that the logic will check whether the whole array contains admin keyword or not and call admin API or Non-Admin API only once.

if (tempAuth && tempAuth.length > 0) {
      this.auth = tempAuth.filter(x => {
        if (x.authority.includes('admin')) {
            // Admin API
            this.getalldetails();
          }
         else {
          // Non Admin API
           this.getUserdetails();
         }
      });

Answer 1

One option is to use the some method to check if the auth criteria is ever met. Then you can use that boolean value to determine what to do next.

if (tempAuth && tempAuth.length > 0) {
  this.auth = tempAuth.some(x => x.authority.includes('admin'));
  if (this.auth) {
    this.getalldetails();
  } else {
    this.getUserdetails();
  }
}

Answer 2

You can use some() method to determine whether at least one element in the array tempAuth includes authority as admin. If yes, then we set getalldetails to this.auth else we pass getUserdetails

if (tempAuth && tempAuth.length > 0) {
   var found = tempAuth.some(x => x.authority.includes('admin'));
   this.auth = found ? this.getalldetails() : this.getUserdetails();
}

Answer 3

The array function some returns a boolean if the condition is true for at least 1 item.

if (tempAuth && tempAuth.length > 0) {
  const isAdmin = tempAuth.some(x => x.authority.includes('admin'));
  if (isAdmin) {
    // Admin API
    this.getalldetails();
  } else {
    // Non Admin API
    this.getUserdetails();
  }
}