Python 按另一个字典值过滤字典列表

Question

I have the below list of dictionaries & a dictionary, I want to return the person name if there's a match

mydblist = [{'name': 'Alice', 'AGATC': '2', 'AATG': '8', 'TATC': '3'},{'name': 'Bob', 'AGATC': '4', 'AATG': '1', 'TATC': '5'},{'name': 'Charlie', 'AGATC': '3', 'AATG': '2', 'TATC': '5'}]

dna_dict = {'AGATC': 4, 'AATG': 1, 'TATC': 5}

so now I need to print name 'Bob' from the list of dictionaries mydict_list, as he has a full match with dna_dict,

or print no match in case no match found

Many thanks for your support in advance

Answer 1

Using the list provided I wrote the solution below. It's just compare the dict keys. One dict has a str type and other with int type that's why the code convert the type.

def compare_dicts(a, b):
    """
    Compare all keys of A with the same key in B
    """

    for key in a.keys():
        if key in b:

            if a[key] != int(b[key]):
                return False

    return True

for dict_obj in mydblist:
    if compare_dicts(dna_dict, dict_obj):
        print(dict_obj['name'])

Answer 2

Try it

 mydblist = [{'name': 'Alice', 'AGATC': '2', 'AATG': '8', 'TATC': '3'},{'name': 'Bob', 'AGATC': '4', 'AATG': '1', 'TATC': '5'},{'name': 'Charlie', 'AGATC': '3', 'AATG': '2', 'TATC': '5'}]

 # Here i changed dna_dict value integer to string
 dna_dict = {'AGATC': '4', 'AATG': '1', 'TATC': '5'}

    for i in mydblist:
        if i["AGATC"] == dna_dict["AGATC"] and i["AATG"] == dna_dict["AATG"] and i["TATC"] == dna_dict["TATC"]:
            print(i["name"])