[英]Executing ls in a different directory in C using exec
Title is pretty self-explanatory on what I want to do.标题对我想要做什么是不言自明的。
My current try:我目前的尝试:
chdir("/Path/I/want/"); //this is different that the path my program is located at
char * ls_args[] = { "ls" , "ls -l", NULL};
execv(ls_args[0], ls_args);
}
I am not getting any errors or output, any help?我没有收到任何错误或 output,有什么帮助吗?
Execv function needs full path of the command which you have to execute. Execv function 需要您必须执行的命令的完整路径。 So, instead of giving
"ls"
, you should find out where the ls is located in your system by因此,您应该找出 ls 在系统中的位置,而不是给出
"ls"
$ which ls
it will probably be in /bin folder.它可能在 /bin 文件夹中。 So you have to give
"/bin/ls"
to exec.所以你必须把
"/bin/ls"
给exec。 Also any argument to ls should be another member in array. ls 的任何参数也应该是数组中的另一个成员。 So instead of using
所以而不是使用
char * ls_args[] = { "ls", "ls -l", NULL};
use利用
char * ls_args[] = { "/bin/ls", "-l", NULL};
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