使用 openpyxl 读取多个文件

Question

I have a list with a few filenames

ListOfFiles = ['filename1.xlsm', 'filename2.xlsm',...]

What I want to do, is to load these files in an automated way. So I wrote the following:

from openpyxl import load_workbook
for i in LisOfFiles:
    xl = load_workbook(ListOfFiles[i], read_only=True)

However I get a TypeError: list indices must be integers or slices, not str How can I solve this?

Answer 1

Try printing i in the for loop print(i) . Basically you are trying to access an element of a list with a string. In the first iteration this means
i = 'filename1.xlsm' which translates to
LisOfFiles['filename1.xlsm']

However you can only access the elements of a list with a number ie LisOfFiles[0] works fine.

The solution is to directly use i as input to load_workbook. However be aware that in every iteration of the loop xl gets overwritten

for i in LisOfFiles: 
    xl = load_workbook(i, read_only= True)

Answer 2

You are already iterating over the list. No need to index it again:

from openpyxl import load_workbook

for path in ListOfFiles:
    xl = load_workbook(path, read_only=True)

Edit

Note that in the code above, xl gets re-assigned every time. This is probably not what you want.

You could capture the workbooks in a list:

from openpyxl import load_workbook

workbooks = []
for path in ListOfFiles:
    workbooks.append(load_workbook(path, read_only=True))

This can be shortened by using a list comprehension :

workbooks = [
    load_workbook(path, read_only=True)
    for path in ListOfFiles
]

If you want to be able to address them by filename, use a dict comprehension :

workbooks = {
    path: load_workbook(path, read_only=True)
    for path in ListOfFiles
}