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获取“列表”object 在 python 中没有属性“tolist”

[英]Getting 'list' object has no attribute 'tolist' in python

I am trying to run pyspark script.我正在尝试运行 pyspark 脚本。 In this script i am executing sql query and creating dataframe after i am trying to change last column position into first but it is giving me error.在这个脚本中,我正在执行 sql 查询并在我尝试将最后一列 position 更改为第一列之后创建 dataframe 但它给了我错误。 Can you please help me how to do this?你能帮我怎么做吗?

code:代码:

if(masterjobname.endswith('ADDR_Phani')):
            df = sqlContext.sql(query)
            print("Target:  "+targetpath )
            w = (Window().orderBy("SOURCE_COLUMN_VALUE"))
            df = df.withColumn("SYSTEM_ID", dense_rank().over(w))
            cols = df.columns.tolist()
            cols = cols[-1:] + cols[:-1]
            df = df[cols]

Okay i got the answer.好的,我得到了答案。

df.columns.values.tolist() gives the list of the columns. df.columns.values.tolist()给出列的列表。

solution:解决方案:

if(masterjobname.endswith('ADDR_Phani')):
            df = sqlContext.sql(query)
            print("Target:  "+targetpath )
            w = (Window().orderBy("SOURCE_COLUMN_VALUE"))
            df = df.withColumn("SYSTEM_ID", dense_rank().over(w))
            cols = df.columns.values.tolist()
            cols = cols[-1:] + cols[:-1]
            df = df[cols]

No matter if your variable is or isn't a list:无论您的变量是或不是列表:

list(var)

You can use it as exception handling;您可以将其用作异常处理; ie ensure that it is indeed a list object.即确保它确实是一个列表 object。

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