我想在 a.csv 文件中保存一个列表。 列表中的每个 \n 都应在文件中创建一个新行

Question

Example list:

line = ['New York;New\nBerlin;Ber\nMelbourne;Mel']

Every second element in my list contains a \n.

with open('file.csv', 'w', newline='') as csvfile:
save = csv.writer(csvfile)
y = list.count("\n")
for line in range(0, y):
    save.writerow(str(list))

How the.csv file should look like:

NewYork;New
Berlin;Ber
Melbourne;Mel

My Goal is to display the list in excel. This should look like this:

New York | New
Berlin | Ber
Melbourn | Mel

| = new colum

How does the saving process needs to look like?

Answer 1

Your list is not a Python list it should be something like this, if it contains one string with \n in it.

lines = ["New York;New\nBerlin;Ber\nMelbourne;Mel"]

or like this if it contains multiple strings with '\n' in it

lines = ["New York;New\nBerlin;Ber\nMelbourne;Mel",
         "Ber\nMelbourne;Mel\nNew York;New\nBerlin",
         ...
         ]

Also it is not very clear what you are trying to achieve from the code you have written, but the question seems to be that you have a list of strings with new line characters in it, and you want to break the line at '\n' while writing it to a csv file.

the code for which is quite simple

import csv
# this list is explained above
lines = ["New York;New\nBerlin;Ber\nMelbourne;Mel", "New York;New\nBerlin;Ber\nMelbourne;Mel"]
lines = [[word] for line in lines for word in line.split('\n')]
with open('file.csv', 'w') as fh:
    csv_writer = csv.writer(fh)
    csv_writer.writerows(lines)  

Additionally since you did not talk about columns, I would suggest please read on CSV files, you might not need a CSV file.

UPDATE

after reading your comment, I believe you have one big string of content, and the changing first two lines in above code to this should work.

content = "first colum first line; second colum first line \n first colum second line; second colum second line"
lines = [line.split(';') for line in content.split('\n')]