SQL 如何使用 datediff 排除数据并且不存在于同一个表中

Question

I'm trying to exclude some data in my query, but wasn't able to figure out myself after searching for keywords.

Above is the example table with columns I have with following query:

SELECT id, date, health, state, reason FROM table1

my goal is excluding (state = START) case and cases when (health = NO && reason = REASON1) if this occurs in 10 minutes after START happen. It's possible to have (health = NO && reason = REASON1) after 10 minutes of START event, and I want to leave them there as is if condition of in 10 minutes doesn't meet.

Below is the goal I wanted to achieve.

Excluding (state = START) was very easy:

SELECT id, date, health, state, reason FROM table1 WHERE state not in ('START')

but I wasn't able to figure out how to exclude (health = NO && reason = REASON1) if this occurs in 10 minutes after START happen part.

My idea was using DATEDIFF and not exists, like following:

SELECT id, date, health, state, reason FROM table1 WHERE state not in ('START') and (health = 'NO' and reason = 'REASON1' and DATEDIFF(minute,(current_date)?,(last starting time)?) < 15)

(current_date)?,(last starting time)? parts I'm not sure how to achieve this. I think I should use NOT EXISTS as well for the second condition, but the one I tried didn't work. Can anyone help or give me direction to go?

Answer 1

If I understand correctly, you can use a window function to calculate the previous start date. Then the filtering is pretty easy:

SELECT id, date, health, state, reason
FROM (SELECT t1.*,
             MAX(CASE WHEN state = 'START' THEN date END) OVER (PARTITION BY id ORDER BY date) as prev_start_date
      FROM table1 t1
     ) t1
WHERE state <> 'START' OR
      (health = 'NO' AND
       reason = 'REASON1' AND
       prev_start_date > date - interval 10 minute
      );