[英]Passing arguments from variable - Python
I'm writing a python script.我正在写一个 python 脚本。 In the script I wrote a function with some arguments that all has defult values.在脚本中,我写了一个 function 和一些 arguments ,它们都有默认值。 Also in the script i have list of tuples, first item in each tuple its the name of the argument from the function, the second is the value.同样在脚本中我有元组列表,每个元组中的第一项是来自 function 的参数的名称,第二项是值。 here is code for example:这是例如代码:
def f(a=0, b=0, c=0):
print(a), print(b), print(c)
args = [('a', 12), ('c', -64)]
Is there some way, when I call the method, to put the value 12 in the 'a' argument and the value -64 in the 'c' argument without do it manualy?当我调用该方法时,是否有某种方法可以将值 12 放入“a”参数中,将值 -64 放入“c”参数中,而无需手动操作? (the value b remains 0). (值 b 保持为 0)。
Thanks for any Help!谢谢你的帮助!
You can build a dictionary then unpack it with **
:你可以建立一个字典,然后用**
解压它:
f(**dict(args))
will output将 output
12
0
-64
def f(a=0, b=0, c=0):
print(a), print(b), print(c)
args = [('a', 12), ('c', -64)]
f(**dict(args))
result:结果:
a = 12
b = 0
c = -64
But better way to use dict但更好的方式来使用 dict
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