[英]Passing on named variable arguments in python
Say I have the following methods: 说我有以下方法:
def methodA(arg, **kwargs):
pass
def methodB(arg, *args, **kwargs):
pass
In methodA I wish to call methodB, passing on the kwargs. 在methodA中,我希望调用methodB,传递kwargs。 However, it seems that if I define methodA
as follows, the second argument will be passed on as positional rather than named variable arguments. 但是,似乎如果我按如下方式定义methodA
,则第二个参数将作为位置而不是命名变量参数传递。
def methodA(arg, **kwargs):
methodB("argvalue", kwargs)
How do I make sure that the **kwargs in methodA gets passed as **kwargs to methodB? 如何确保methodA中的** kwargs作为** kwargs传递给methodB?
Put the asterisks before the kwargs variable. 把星号放在kwargs变量之前。 This makes Python pass the variable (which is assumed to be a dictionary) as keyword arguments. 这使得Python将变量(假定为字典)作为关键字参数传递。
methodB("argvalue", **kwargs)
As an aside: When using functions instead of methods, you could also use functools.partial: 暂且不说:当使用函数而不是方法时,您也可以使用functools.partial:
import functools
def foo(arg, **kwargs):
...
bar = functools.partial(foo, "argvalue")
The last line will define a function "bar" that, when called, will call foo with the first argument set to "argvalue" and all other functions just passed on: 最后一行将定义一个函数“bar”,当调用它时,将调用foo,第一个参数设置为“argvalue”,所有其他函数都被传递:
bar(5, myarg="value")
will call 将会通知
foo("argvalue", 5, myarg="value")
Unfortunately that will not work with methods. 不幸的是,这不适用于方法。
Some experimentation and I figured this one out: 一些实验,我想出了这个:
def methodA(arg, **kwargs): methodB("argvalue", **kwargs) def methodA(arg,** kwargs):methodB(“argvalue”,** kwargs)
Seems obvious now... 现在似乎显而易见......
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