Python 字典：为字典中的所有键创建一个列表，为字典中的所有值创建另一个列表

Question

I have a dictionary which looks like this: Counter({'firstKey': 1708, 'secondKey': 1589, 'thirdKey': 1424})

I would like to have two lists:

First list should list all keys: ['firstKey', 'secondKey', 'thirdKey']

Second list should list all values: [1708, 1589, 1424]

Please help

Answer 1

Usingdict.keys() and dict.values() and casting them to list :

d = {'firstKey': 1708, 'secondKey': 1589, 'thirdKey': 1424}

print(list(d.keys()))
print(list(d.values()))

OUTPUT:

['firstKey', 'thirdKey', 'secondKey']                                                                                                                          
[1708, 1424, 1589]

Answer 2

Try list(dict.keys()) and list(Counter.values())

>>> counter= Counter({'firstKey': 1708, 'secondKey': 1589, 'thirdKey': 1424})
>>> Keys = list(counter.keys())
>>> Keys
['firstKey', 'secondKey', 'thirdKey']
>>> Vals = list(counter.values())
>>> Vals
[1708, 1589, 1424]
>>> 

Answer 3

Cast list() to the dictionary to get the keys in a list, and cast list() to the dict.values() to get the values in a list:

>>> from collections import Counter
>>> d = Counter({'firstKey': 1708, 'secondKey': 1589, 'thirdKey': 1424})
>>> l1 = list(d)
>>> l1
['firstKey', 'secondKey', 'thirdKey']
>>> l2 = list(d.values())
>>> l2
[1708, 1589, 1424]

Could also usedict.keys() :

>>> l1 = list(d.keys())
>>> l1
['firstKey', 'secondKey', 'thirdKey']

But not really needed since list(d) will give you the keys by default.

Answer 4

You could assign the two list variables in one line like this:

d = Counter({'firstKey': 1708, 'secondKey': 1589, 'thirdKey': 1424})

keys,values = map(list,zip(*d.items()))

output:

print(keys)
print(values)

['firstKey', 'secondKey', 'thirdKey']
[1708, 1589, 1424]