我正在尝试制作一个 function 将 integer 转换为不返回字符串的字符串。 我该如何解决这个问题？

Question

I'm trying this code to convert integers to string It's printing the values but isn't returning anything to the calling function

char* itoa(int num, int num_len)
{
    char str[num_len+2];
    int i;
    //if the num is 0
    if(num == 0)
        strcpy(str, "0");
    //if the num is negetive then we append a '-' sign at the beginning
    //and put '\0' at (num_len+1)th position 
    else if(num < 0)
    {
        num *= -1;
        str[num_len+1] = '\0';
        str[0] = '-';
        i = num_len+1;
    }
    //we put '\0' (num_len)th position i.e before the last position
    else
    {
        str[num_len] = '\0';
        i = num_len;
    } 

    for(;num>0;num/=10,i--)
    {
        str[i] = num%10 + '0';
        printf("%c ",str[i]);//for debugging
    }

    return str;
}

Answer 1

I just forgot that rule. thank you very much

char* itoa(int num, int num_len,char* str)
{
    int i;
    str = (char*)malloc((num_len + 2)*sizeof(char)); 
    if(num == 0)
        strcpy(str, "0");
    else if(num < 0)
    {
        num *= -1;
        str[num_len+1] = '\0';
        str[0] = '-';
        i = num_len;
    }
    else
    {
        str[num_len] = '\0';
        i = num_len-1;
    } 

    for(;num>0;num/=10,i--)
    {
        str[i] = num%10 + '0';
        printf("%c ",str[i]);
    }

    return str;
}