我正在尝试显示使用输入 function 获得的字符串的索引值

Question

index=0

while True:
    stri=input("enter the strings : ")
    if stri=="Exit" or stri=="exit":
        break
    for indexes in stri:
        letter=stri[index]
        print(index, letter)
        index=index+1

After displaying the index value of the first string entered it is showing an error

    enter the strings : abcdfg
0 a
1 b
2 c
3 d
4 f
5 g
enter the strings : qwerty
Traceback (most recent call last):
  File "len.py", line 10, in <module>
    letter=stri[index]
IndexError: string index out of range

this is the error I get

Answer 1

As you are already looping through the string, you don't need the extra index:

while True:
    stri=input("enter the strings : ")
    if stri=="Exit" or stri=="exit":
        break
    for index, letter in enumerate(stri):
        print(index, letter)

Answer 2

You can try something like this

while True:
    stri=input("enter the strings : ")
    if stri.lower() == 'exit':
        break
    for index, value in enumerate(stri):
        print(index, " "+ value)

Answer 3

you don't need to keep the index use the pointer that you are using for writing the string charcters

# index=0

while True:
    stri=input("enter the strings : ")
    if stri=="Exit" or stri=="exit":# you can directly use lower()
        break
    for indexes in range(len(stri)):
        letter=stri[indexes]
        print(indexes+1, letter)

Alternate solution

while True:
    stri=input("enter the strings : ")
    if stri=="Exit" or stri=="exit":# you can directly use lower()
        break
    index=0
    for indexes in range(len(stri)):
        letter=stri[index]
        print(index+1, letter)
        index+=1

Answer 4

you need to init the index after each input

while True:
    index=0
    stri=input("enter the strings : ")
    if stri=="Exit" or stri=="exit":
        break
    for indexes in stri:
        letter=stri[index]
        print(index, letter)
        index=index+1