从 python 中的该数组中删除每隔一个元素

Question

I am using codewars.com to exercise my learning in python 3. I am new to this language. This is the exercise that I have to do.

Take an array and remove every second element out of that array. Always keep the first element and start removing with the next element.

And this is an example, to make it clearer:

my_list = ['Keep', 'Remove', 'Keep', 'Remove', 'Keep', ...]

I understand that the elements of an array start counting from zero, I also understand that starting from one, odd numbers start counting. If I delete the items with odd keys, I would be doing the exercise. I have no idea where to start, but this was my attempt:

def remove_every_other(my_list):

    for i in my_list:
        if my_list[i] % 2 != 0:
            my_list[i]
    return my_list

any other idea?

Answer 1

You can do slicing:

new_list = my_list[::2]