尝试运行代码 x 次，如果失败 x 次引发异常

Question

There is a code that randomly raises an error.

When the code fails, I want to rerun it, but if it fails x times I want to raise a custom error.

Is there a proper way to do it in Python?

#

I am thinking the following but it doesn't seem to be the best.

 class MyException(Exception): pass try: for i in range(x): try: some_code() break except: pass except: raise MyException("Check smth")

Answer 1

You can do it like this

for i in range(x):
    retries = <how many times you want to try> 
    while retries: # This could be while 1 since the loop will end in successful run or with exception when retries run out. 
        try:
            some code
            break # End while loop when no errors
         except:
            retries =- 1
            if not retries:
                raise MyException("Check smth")

Answer 2

Just create an infinite loop that will break on success, and count the errors in the except block:

max_errors = 7

errors = 0
while True:
    try:
        run_code()
        break
    except ExceptionYouWantToCatch:  # You shouldn't use a bare except:
        errors += 1
        if errors > max_errors:
            raise MyException

Another way to do it:

max_errors = 7


for run in range(max_errors):
    try:
        run_code()
        break
    except ExceptionYouWantToCatch:  # You shouldn't use a bare except:
        pass
else:  # will run if we didn't break out of the loop, so only failures
    raise MyException