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在 SQL 服务器中搜索序列模式

[英]Search sequence pattern in SQL Server

I have records like this and I want to search in SQL Server by pattern and sequence like (50,54,50) in value field it should return 02,03,04 any one have idea to do this.我有这样的记录,我想在 SQL 服务器中按模式和序列(如(50,54,50))在值字段中搜索它应该返回 02,03,04 任何人都知道这样做。

======================================
Id             Date             Value
01             2020-01-01       50
02             2020-01-02       50
03             2020-01-03       54
04             2020-01-04       50
05             2020-01-05       35
06             2020-01-06       98
07             2020-01-07       13
======================================

There is a request on the user voice site Add support for Row Pattern Recognition in T-SQL (SQL:2016 features R010 and R020) which I believe would allow for this.用户语音站点上有一个请求添加对 T-SQL 中行模式识别的支持(SQL:2016 功能 R010 和 R020) ,我相信这将允许这样做。

In the meantime this should do what you need与此同时,这应该做你需要的

WITH T AS
(
SELECT *, 
       LAG(Id) OVER (ORDER BY Id) AS PrevId, 
       LAG(value) OVER (ORDER BY Id) AS PrevValue,
       LEAD(Id) OVER (ORDER BY Id) AS NextId, 
       LEAD(value) OVER (ORDER BY Id) AS NextValue
FROM YourTable
)
SELECT PrevId, Id, NextId
FROM T
WHERE PrevValue = 50 AND Value =54 AND NextValue = 50

If you wanted a more flexible approach, you can use cross apply :如果您想要更灵活的方法,可以使用cross apply

select t2.*
from t cross apply
     (select string_agg(id, ',') within group (order by date) as ids,
             string_agg(value, ',') within group (order by date) as vals
      from (select top (3) t2.*
            from t t2
            where t2.date >= t.date
            order by t2.date
           ) t2
     ) t2
where vals = '50,54,50';

Here is a db<>fiddle. 是一个 db<>fiddle。

If string_agg() were supported as a window function, you could use:如果支持string_agg()作为 window function,您可以使用:

select t.*
from (select t.*,
             string_agg(id, ',') within group (order by date) over (order by id rows between current row and 2 following) as ids,
             string_agg(value, ',') within group (order by date) over (order by id rows between current row and 2 following) as vals
      from t
     ) t
where vals = '50,54,50';

But alas, it is not.但很可惜,事实并非如此。

If I get your requirement correct, yo can try this below logic developed with the help of LAG and LEAD-如果我的要求正确,您可以尝试在 LAG 和 LEAD 的帮助下开发的以下逻辑-

DEMO HERE 在这里演示

WITH CTE
AS
(
    SELECT Id,Date,
    LAG(value,2) OVER(ORDER BY id) lag_2,
    LAG(value,1) OVER(ORDER BY id) lag_1,
    Value c_val,
    LEAD(value,1) OVER(ORDER BY id) lead_1,
    LEAD(value,2) OVER(ORDER BY id) lead_2
    FROM your_table
)

SELECT Id,Date,
CASE 
    WHEN (lag_2 = 50 AND lag_1 = 54 AND c_val = 50) OR
         (lag_1 = 50 AND c_val = 54 AND lead_1 = 50) OR
         (c_val = 50 AND lead_1 = 54 AND lead_2 = 50)
         THEN (
             CASE 
                 WHEN lead_1 = 54 THEN 02
                 WHEN c_val = 54 THEN 03
                 WHEN lag_1 = 54 THEN 04
             END
         )
    ELSE c_val
END
FROM CTE

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