简体   繁体   English

Flutter 来自多个集合的 Firestore 搜索

[英]Flutter Firestore search from more than 1 collection

So what I'm trying to do is search from 2 or more collection.所以我想做的是从 2 个或更多集合中搜索。 Here's my collection:这是我的收藏:

Tier-1
Tier-2
Tier-3

Let's say I want to search with key "name" and what I want to achieve is, it will searching from Tier-1 to Tier-3.假设我想用键“名称”进行搜索,而我想要实现的是,它将从第 1 层搜索到第 3 层。 If there's no document equal to "name" from Tier-1, it will continue to Tier-2, if there's document equal to "name" at Tier-2, it will stop and return the document.如果Tier-1没有与“name”相等的文件,它将继续到Tier-2,如果在Tier-2有与“name”相等的文件,它将停止并返回该文件。 Is it possible to achieve?有没有可能实现? or my logic is totally wrong或者我的逻辑完全错误

Basically what you are saying, is that you have the following structure:基本上你要说的是,你有以下结构:

Tier-1 (collection) -> docId(document) -> Tier-2 (collection) -> docId(document) -> Tier-3 (collection) -> docId(document)

You can do the following:您可以执行以下操作:

  void getData() {
    Firestore.instance
        .collection("Tier-1")
        .where("name", isEqualTo: "peter")
        .getDocuments()
        .then((querySnapshot) {
      querySnapshot.documents.forEach((result) {
        if (result.exists) {
          print(result.data);
        } else {
          Firestore.instance
              .collectionGroup("Tier-2")
              .where("name", isEqualTo: "peter")
              .getDocuments()
              .then((querySnapshot) {
            querySnapshot.documents.forEach((result) {
              if (result.exists) {
                print(result.data);
              } else {
                Firestore.instance
                    .collectionGroup("Tier-3")
                    .where("name", isEqualTo: "peter")
                    .getDocuments()
                    .then((querySnapshot) {
                  querySnapshot.documents.forEach((result) {
                    if (result.exists) {
                      print(result.data);
                    } else {}
                  });
                });
              }
            });
          });
        }
      });
    });
  }

First you check the top collection Tier-1 , if it returns no result, then you need to check the subcollection Tier-2首先检查顶部集合Tier-1 ,如果没有返回结果,则需要检查子集合Tier-2

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM