[英]how to group items and convert to list in java
I have DTO like following我有像下面这样的 DTO
public class UserDTO implements Serializable {
private String id;
private String fullName;
private String phone;
private String role;
private List<String> roleList;
public UserDTO(String id, List<String> roleList) {
super();
this.id = id;
this.roleList = roleList;
}
}
I have the list of UserDTO
where roleList
is not populated but role
is populated.我有
UserDTO
列表,其中没有填充roleList
列表,但填充了role
。 The problem is role
could be multiple but somehow i can't manage to get the list in a single query.问题是
role
可能是多个但不知何故我无法设法在单个查询中获取列表。 So, I want to group by id and generate roleList
.所以,我想按 id 分组并生成
roleList
。
For example, I have the following rows:例如,我有以下行:
id fullName phone role roleList
------------------------------------------------
abc Sarwar 017xxx admin NULL
abc Sarwar 017xxx operator NULL
I want it to be like the following
abc Sarwar 017xxx NULL ArrayList<String>(admin, operator)
I have tried the following but it is not working (shouldn't though but i can't figure out what it should be) that's why i am seeking your help:我尝试了以下方法,但它不起作用(不应该,但我不知道它应该是什么)这就是我寻求你帮助的原因:
Map<String, List<UserDTO>> resultsWithSameIdAndName = users.stream()
.collect(Collectors.groupingBy(r -> r.getId()));
List<UserDTO> mergedResults = resultsWithSameIdAndName.entrySet().stream()
.map(e -> new UserDTO(e.getKey(),
e.getValue().stream().map(r -> r.getRole()).collect(Collectors.toList())))
.collect(Collectors.toList());
Thanks in advance.提前致谢。
This might work for you:这可能对您有用:
import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;
public class UserDTO {
private String id;
private String fullName;
private String phone;
private String role;
private List<String> roleList;
public UserDTO(String id,String fullName,String phone,String role) {
this.id = id;
this.fullName = fullName;
this.phone = phone;
this.role =role;
}
public UserDTO(UserDTO oldObject,String key, List<String> collect) {
this.id = key;
this.fullName = oldObject.getFullName();
this.phone = oldObject.getPhone();
this.roleList = collect;
}
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public String getFullName() {
return fullName;
}
public void setFullName(String fullName) {
this.fullName = fullName;
}
public String getPhone() {
return phone;
}
public void setPhone(String phone) {
this.phone = phone;
}
public String getRole() {
return role;
}
public void setRole(String role) {
this.role = role;
}
public List<String> getRoleList() {
return roleList;
}
public void setRoleList(List<String> roleList) {
this.roleList = roleList;
}
public static void main(String[] args) {
ArrayList<UserDTO> list = new ArrayList<>();
list.add(new UserDTO("ASD", "John", "12345", "user"));
list.add(new UserDTO("ASD", "John", "12345", "admin"));
list.add(new UserDTO("SDB", "Smith", "12345", "super user"));
list.add(new UserDTO("SDB", "Smith", "12345", "admin"));
list.add(new UserDTO("DFG", "Neo", "12345", "user"));
Map<String, List<UserDTO>> resultsWithSameIdAndName = list.stream().collect(Collectors.groupingBy(UserDTO::getId));
List<UserDTO> mergedResults = resultsWithSameIdAndName.entrySet().stream()
.map(e -> new UserDTO(
e.getValue().get(0),
e.getKey(),
e.getValue().stream().map(UserDTO::getRole).collect(Collectors.toList())))
.collect(Collectors.toList());
System.out.println(mergedResults);
}
}
Only changes that I done is added a parameter in constructor which takes an UserDTO
object.只有我所做的更改是在构造函数中添加一个参数,该参数采用
UserDTO
object。
Your code should work.您的代码应该可以工作。 I added another way to this.
我为此添加了另一种方法。
First prepare map for roleList
by user id
首先通过用户
id
为角色列表准备roleList
Map<String, List<String>> resultsWithSameIdAndName = users.stream()
.collect(Collectors.groupingBy(UserDTO::getId,
Collectors.mapping(d-> d.getRole(), Collectors.toList())));
Then create unique user list by user id
然后通过用户
id
创建唯一的用户列表
List<UserDTO> uniqueUsers = users.stream()
.collect(Collectors.collectingAndThen(Collectors.toCollection(() -> new TreeSet<>(Comparator.comparing(UserDTO::getId))),ArrayList::new));
And get role list from map and set for every user并从 map 获取角色列表并为每个用户设置
for(UserDTO user :uniqueUsers) {
user.setRoleList(resultsWithSameIdAndName.get(user.getId()));
}
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