[英]How to change datetime resolution
Is there a simple way to state that有没有一种简单的方法来 state
a = '2020-01-01 19:30:33.996628'
b = '2020-01-01 19:30:34'
a
and b
are equal. a
和b
相等。 If the time resolution of a
is changed to second, then a
could be equal to b
.如果a
的时间分辨率更改为秒,则a
可能等于b
。 How to implement it with code?如何用代码实现它?
timedelta
difference between 1e6
and a.microsecond
添加1e6
和a.microsecond
之间的timedelta
差异from datetime import timedelta, datetime
a = datetime.fromisoformat('2020-01-01 19:30:33.996628')
a = a + timedelta(microseconds=(1e6 - a.microsecond))
print(a)
>>> datetime.datetime(2020, 1, 1, 19, 30, 34)
print(a.strftime('%Y-%m-%d %H:%M:%S'))
>>> 2020-01-01 19:30:34
.replace(microsecond=0)
使用.replace(microsecond=0)
from datetime import datetime
a = datetime.fromisoformat('2020-01-01 19:30:33.996628')
print(a)
>>> datetime.datetime(2020, 1, 1, 19, 30, 33, 996628)
a = a.replace(microsecond=0)
print(a)
>>> datetime.datetime(2020, 1, 1, 19, 30, 33)
if you treat both of them as datetime
objects, you can use arithmetic operators on them.如果将它们都视为datetime
时间对象,则可以对它们使用算术运算符。 For example, you can subtract them and check if the result satisfy a condition (like less then one minute different) as you wise例如,您可以明智地减去它们并检查结果是否满足条件(例如相差不到一分钟)
An easier way to use rounding for comparison:-使用舍入进行比较的更简单方法:-
import datetime
from dateutil import parser
a = '2020-01-01 19:30:33.996628'
b = '2020-01-01 19:30:34'
a = parser.parse(a)
b = parser.parse(b)
a == b
False
format_str = '%Y-%m-%d %H:%M'
a_rounded = datetime.datetime.strptime(datetime.datetime.strftime(a, format_str), format_str)
b_rounded = datetime.datetime.strptime(datetime.datetime.strftime(b, format_str), format_str)
a_rounded == b_rounded
True
To this you can add flexibility according to your need like I have rounded up to comparison in Minutes
.为此,您可以根据需要增加灵活性,就像我在Minutes
中进行的比较一样。 So in your case the format_str would be like this:-因此,在您的情况下, format_str 将是这样的:-
format_str = '%Y-%m-%d %H:%M:%S'
The function datetime_round_s()
below rounds to the closest second (like usual rounding of numbers):下面的 function datetime_round_s()
舍入到最接近的秒数(就像通常的数字舍入一样):
import datetime
def datetime_round_s(date_time: datetime.datetime) -> datetime.datetime:
return (date_time + datetime.timedelta(microseconds=5e5)).replace(microsecond=0)
a = datetime.datetime.fromisoformat('2020-01-01 19:30:33.996628')
b = datetime.datetime.fromisoformat('2020-01-01 19:30:34')
print(a)
print(datetime_round_s(a))
print(datetime_round_s(a) == b)
otuput:输出:
2020-01-01 19:30:33.996628
2020-01-01 19:30:34
True
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