我在这个脚本中使用 if / then 有什么问题？

Question

I'm learning if and then statements. I'm trying to write code that takes any decimal number input (like 2, 3, or even 5.5) and prints whether the input was even or odd (depending on whether the input is actually an integer.)

I get an error in line 8

#input integer / test if any decimal number is even or odd

inp2 = input("Please enter a number: ")

the_number = str(inp2)

if "." in the_number:
    if int(the_number) % 1 == 0
        if int(the_number) % 2 == 0:
            print("Your number is even.")
        else:
            print("Your number is odd.")
    else:
        print("You dum-dum, that's not an integer.")
else:
    the_number = int(inp2)
    if the_number % 2 == 0:
        print("Your number is even.")
    else:
        print("Your number is odd.")

I'm just starting with python so I appreciate any feedback.

Answer 1

You have to include a colon at the end of second if statement, like you did in your other conditional statements.

if int(the_number) % 1 == 0:

Next time, give a closer look at the error message. It'll give you enough hints to fix it yourself, and that's the best way to learn a language.

Answer 2

EOL.

You forgot a : . Line 8 should read if int(the_number) % 1 == 0: .

Answer 3

Try putting the: at the end of the if statement if int(the_number) % 1 == 0:

Answer 4

You can test your input as following code snippet

num = input('Enter a number: ')

if num.isnumeric():
    print('You have entered {}'.format(num))
    num = int(num)
    if num%2:
        print('{} is odd number'.format(num))
    else:
        print('{} is even number'.format(num))
else:
    print('Input is not integer number')