[英]Extracting Results from “Result-Page” With Selenium in Python
Unfortunately I have a little problem with the realization of my Python program.不幸的是,我的 Python 程序的实现有点问题。 At one point I can't get any further.
在某一时刻,我无法再进一步了。 The program should do the following:
该程序应执行以下操作:
The problem here is that I can't get the source code from the search results page.这里的问题是我无法从搜索结果页面获取源代码。 I only get the source code of the start page Does anyone know a solution?
我只得到起始页的源代码有人知道解决方案吗?
Thanks in advance.提前致谢。
So far my program looks like this:到目前为止,我的程序如下所示:
import selenium.webdriver as webdriver
def get_results(search_term):
#this is the site, where I want to do the search
url="https://www.startpage.com"
browser = webdriver.Firefox()
browser.get(url)
search_box = browser.find_element_by_id("q")
#search in the search box after the search term
search_box.send_keys(search_term)
search_box.submit()
#print(browser.page_source) would give the result of the startpage (not the result page)
sub="dog"
print(source_code.count("dog"))
#counts zero times because it searchs for "dog" at the startpage
get_results("dog")
You can do it this way: Just make a loop in which you always add an elment to a list (can be a number or a letter, for example) when this term is found.你可以这样做:只要创建一个循环,当找到这个词时,你总是将一个元素添加到列表中(例如,可以是数字或字母)。
To do this you have to save the source code in a variable and then simply search for the term in it.为此,您必须将源代码保存在变量中,然后简单地在其中搜索术语。 When it is found you simply add a number to a list with
.append()
and then at the end you check the length of the list with len(list)
.找到后,您只需使用
.append()
将一个数字添加到列表中,然后在最后使用len(list)
检查列表的长度。
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