替换 PHP 中的 UTF-8 KeyCap 数字字符

Question

I am trying to replace these [0️⃣1️⃣2️⃣2️⃣3️⃣4️⃣5️⃣6️⃣7️⃣8️⃣9️⃣] UTF characters from a string. But somehow all other digit characters are also getting replaced. I've tried using replacing by range. Here is what i've tried

$post = '  🗡️7️⃣8️⃣6️⃣🗡️  ';

$post = preg_replace('/[\x{0030}-\x{0040}]/u', '', $post);

echo $post;

How to do it

Answer 1

You may remove all those digits that have diacritic marks after them (all those numbers you shared are actually digits with some diacritics after):

preg_replace('/[0-9]\p{M}+/u', '', $post)

The [0-9] will match ASCII digits from 0 to 9 , and the \p{M}+ matches 1 or more diacritic marks. So, regular ASCII digits will not be removed.

See the regex demo

Answer 2

I'm not sure what result you need.

The key's one to nine are combinations how "5\u{fe0f}\u{20e3}". Key Ten is the unicode symbol "\u{1f51f}". If only these symbols are to be removed, you must do this:

$post = '123🗡️0️⃣1️⃣2️⃣2️⃣3️⃣abc4️⃣x8x5️⃣6️⃣7️⃣8️⃣9️⃣🔟🗡️56';

$post = preg_replace('~[0-9]\x{fe0f}\x{20e3}|\x{1f51f}~u', '', $post);

echo $post;

Output:

123🗡️abcx8x🗡️56