[英]How to transform a data frame with identical column names
I have a df like:我有一个像这样的df:
df <- data.frame( name = c("mouse", "rat"), cont = c(27L, 83L), cont = c(43L, 45L), cont = c(18L, 54L),
treat = c(49040L, 53522L), treat = c(48570L, 22235L), treat = c(138888L, 345667L))
name cont cont cont treat treat treat
mouse 27 43 18 49040 48570 138888
rat 83 45 54 53522 22235 345667
I performed melt
function by meltData <- melt(df)
on the df but I get all row same, I mean:我在df上通过
meltData <- melt(df)
执行了melt
function 但我得到的所有行都相同,我的意思是:
variable value
cont 27
cont 83
cont 27
cont 83
treat 49040
treat 53522
treat 49040
treat 53522
.
.
.
desired output should be:所需的 output 应该是:
variable value
cont 27
cont 83
cont 43
cont 45
treat 49040
treat 53522
treat 48570
treat 22235
.
.
.
I tried different ways of melting but couldn't figure out what I'm missing.我尝试了不同的融化方式,但无法弄清楚我错过了什么。 Any help would be appreciated.
任何帮助,将不胜感激。
You can use data.table::melt()
instead:您可以使用
data.table::melt()
代替:
library(data.table)
setDT(df)
melt(df, id.vars = "name")[, variable := sub("\\..+", "", variable)
][, !"name"]
variable value
1: cont 27
2: cont 83
3: cont 43
4: cont 45
5: cont 18
6: cont 54
7: treat 49040
8: treat 53522
9: treat 48570
10: treat 22235
11: treat 138888
12: treat 345667
Or stack()
from base R:或来自基础 R 的
stack()
:
dfl <- stack(df[-1])
dfl$ind <- sub("\\..+", "", dfl$ind)
dfl
values ind
1 27 cont
2 83 cont
3 43 cont
4 45 cont
5 18 cont
6 54 cont
7 49040 treat
8 53522 treat
9 48570 treat
10 22235 treat
11 138888 treat
12 345667 treat
Data数据
df <- data.frame(
name = c("mouse", "rat"),
cont = c(27L, 83L),
cont = c(43L, 45L),
cont = c(18L, 54L),
treat = c(49040L, 53522L),
treat = c(48570L, 22235L),
treat = c(138888L, 345667L)
)
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