我正在尝试一次打印多行，每行在 python 2.7.11 中都有一个设定速度的延迟打印

Question

Basically,

Delay Print 1

Multiple lines at once test.

The big brown fox jumped over the lazy dog.

Should all print at the same time, while using this function

import time
import sys

text_speed = raw_input("What speed? > ")

def delay_print(s):
    for c in s:
        sys.stdout.write(c)
        sys.stdout.flush()
        if text_speed == "fast":
            time.sleep(0.075)

        elif text_speed == "slow":
            time.sleep(.275)

        elif text_speed == "normal":
            time.sleep(.175)

delay_print("Delay Print 1 \n")
delay_print("Multiple lines at once test. \n")
delay_print("The big brown fox jumped over the lazy dog. \n")

Is that possible?

When I run it, it will delay print each string one after the other, but I can't seem to find a way to make all 3 lines print at once. Even without the delay print.

Answer 1

well it depends, the thing that is happening right now is that you are giving the order to execute 3 times the function with different attributes, but if I did understand you, you want to execute these 3 functions in a parallel way to each other so here is a reading you can use on multiprocessing http://docs.python.org/2/library/multiprocessing.html I hope it helps.

Answer 2

I'm not sure how you would make it 3 lines, but the program from this github link makes a progress bar in the console, and there are things after the part that moves, so you might be able to find a way to also add a new line in this setup.

import math
import sys
import time

END = 170

MAX_LEN = 30

def get_progressbar_str(progress):
    BAR_LEN = int(MAX_LEN * progress)
    return ('[' + '=' * BAR_LEN +
            ('>' if BAR_LEN < MAX_LEN else '') +
            ' ' * (MAX_LEN - BAR_LEN) +
            '] %.1f%%' % (progress * 100.))

for i in range(END + 1):
    time.sleep(0.01)
    progress = 1.0 * i / END
    sys.stderr.write('\r\033[K' + get_progressbar_str(progress))
    sys.stderr.flush()
sys.stderr.write('\n')
sys.stderr.flush()

you might want to put this at the end so the console doesn't close out after.

while True:
    time.sleep(1)

note: this has to be ran from a.py file, not from idle to see the progress bar properly.