Kotlin 具有多个默认 arguments 的函数：如何忽略值？

Question

Let's say I've got the following function:

fun main(args: Array<String>) {
    demo("Test", 48)
}

fun demo(a: String = "a not given", b: Int = 0) {
    println("$a und $b")
}

How would I invoke demo(), providing only the second parameter (the integer)?

Answer 1

It will work try it

fun main(args: Array<String>) {
    demo(b = 48)
}