调用 Python function 并从 ZDFFF0A7FA1A55C64C1A49666C19 传递 windows 参数

Question

I have a Python function that I want to run from the context-menu. I am using the Windows Registry to call the function when a file is right clicked, and I want the function to receive the file selected.

The context menu item looks something like the Random Commands option .

The function I wish to run is foo1() in the file test1 :

# in script test1.py

def foo1():
    import sys
    print(sys.argv)

I tried approaching the problem using the python -c switch to directly call the function:

 python -c "import test1; test1.foo1()" %1

However, the value of sys.argv after selecting the file and executing is ['-c'] , which doesn't include the file selected.

I also tried using an argument parser to dynamically import and run the function:

# in file registry_parser.py

import argparse
import os
import sys


if __name__ == '__main__':
    parser = argparse.ArgumentParser()
    parser.add_argument('-n', '--func_name')
    parser.add_argument('-f', '--file_name')
    parser.add_argument('-p', '--file_path')

    args = vars(parser.parse_args())
    sys.path.insert(0, args['file_path'])

    exec(f"import {args['file_name']}")
    exec(f"{args['file_name']}.{args['func_name']}(sys.argv)")

And the function I would call from the registry is (paths simplified):

registry_parser.py --func_name foo1 --file_name test1 --file_path "[PATH TO registry_parser.py]" %1

However, I either get an error registry_parser.py: error: unrecognized arguments: %1 or the " %1 " is parsed quite literally and ends up as a value in sys.argv.

Any help is appreciated.

Answer 1

So on all the forums I asked I never received a correct answer, but I found this Reddit Post that has an example to a solution. Hope this helps someone else.