使用 SixLabors.ImageSharp 在 C# 中创建新的 Image 实例

Question

I am trying to create new instance of Image class with SixLabors.Imagesharp but I got error. The system I work with used the old ImageSharp and We want to renew nuget packages and use SixLabors.ImageSharp instead.

The code used to be like this: OLD Code with ImageSharp:

var resultImage = new Image<Rgba32>(outputImageWidth, outputImageHeight);

The new code I try to write with SixLabors.ImageSharp is exactly the same but this time I got the massage:

Severity Code Description   Project File Linem Suppression State
Error CS0315 The type 'SixLabors.ImageSharp.PixelFormats.Rgba32' cannot be used as type parameter 'TPixel' in the generic type or method 'Image<TPixel>'. There is no boxing conversion from 'SixLabors.ImageSharp.PixelFormats.Rgba32' to '?'.

I tried a lot of other ways to create a new Image but I failed. Do you have any idea how I can create new Image using SixLabors.Imagesharp?

Answer 1

The namespace for the pixel format has changed so your code is missing an import.

using SixLabors.ImageSharp.PixelFormats;

The following code compiles and runs for 1.0.0-rc0001

using (var image = new Image<Rgba32>(1000, 1000))
{
    // Do something
}

Documentation

Answer 2

Per the Documentation , the constructor does not take the Generic so modify as below and try.

var resultImage = new Image(outputImageWidth, outputImageHeight);

EDIT: Corrected the Documentation Link. Thanks @James