TypeError：只能将元组（不是“str”）连接到元组。 小部件的问题

Question

Im trying to get information off a website into a widget, it works but i want to have each piece of text it 'finds' to be displayed on a new line. I've tried + '/n' and + ''' ''') but i get the same error.

def Supplies_scraper():
    if instorechoices1.counter !=1:
        url='(url)'
        web_page=urlopen(url)
        html_code=web_page.read().decode("UTF-8")
        web_page.close()
        products = (findall('''data-desc =(.*?)data-price =''',html_code))[:5],


        shopping_list.delete(0.0, END)
        shopping_cart.delete(0.0, END)



        if products:
            shopping_list.insert(0.0, products + '/n')


            shopping_list.insert(0.0, '''Source: (URL)
''')
            shopping_list.insert(0.0,'''--------{ Best Health Supplies }-------
''')

    elif instorechoices1.counter ==1:
        shopping_list.delete(0.0, END)
        shopping_list.insert(END, 'Due to shortages there is only 1 of each item category per order'+ '\n')

    if instorechoices1.counter != 2:
        instorechoices1.counter +=1

Answer 1

Notice that you have trailing, in this line

products = (findall('''data-desc =(.*?)data-price =''',html_code))[:5],

which mean that after it products is tuple , attempt of concatenating tuple with str or str with tuple will result in

TypeError: can only concatenate tuple (not "str") to tuple

Is that trailing , intentional in your code? If not remove it and please check what type it is, for example by doing:

products = (findall('''data-desc =(.*?)data-price =''',html_code))[:5]
print(type(products))

If it is str then you might concatenate it with \n , if it is tuple or list you need convert it for str first, if all elements of list or tuple are str s you might use .join following way:

my_tuple = ('1','2','3')
my_list = ['1','2','3']
joined_tuple = ','.join(my_tuple)
joined_list = ','.join(my_list)
print(joined_tuple)  # 1,2,3
print(joined_list)  # 1,2,3