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Flutter/Dart 组按日期列出

[英]Flutter/Dart group list by date

I have following list of maps,我有以下地图列表,

[
   {
      "FullName":"Harry Potter",
      "DateOfBirth": "2020/02/16",
      "Department":"Branch Operation",
      "BirthDay":"Friday"
   },
   {
      "FullName":"John Wick",
      "DateOfBirth": "2020/02/16",
      "Department":"Finance",
      "BirthDay":"Friday"
   },
   {
      "FullName":"Solomon Kane",
      "DateOfBirth":2020/02/19,
      "Department":"Loan",
      "BirthDay":"Monday"
   }
]

I would like to manipulate above data such that data are grouped by their DateOfBirth , so that result would look like this.我想操作上面的数据,使数据按它们的DateOfBirth分组,所以结果看起来像这样。

[
   {
      "DateOfBirth": "2020/02/16",
      "BirthDay": "Friday",
      "Data":[
         {
            "FullName": "Harry Potter",
            "Department":"Branch Operation",
         },
         {
            "FullName":"John Wick",
            "Department":"Finance",
         }
      ]
   },
   {
      "DateOfBirth": "2020/02/19",
      "BirthDay": "Monday",
      "Data":[
         {
            "FullName":"Solomon Kane",
            "Department":"Loan"
         }
      ]
   },
]

In Javascript, this can be achieved by using reduce function and then using Object key mapping.在 Javascript 中,这可以通过使用reduce function 然后使用 Object 键映射来实现。 I also know dart has useful package called collection我也知道 dart 有有用的 package 叫collection

As I am new to dart and flutter, I am not sure how to do.由于我是 dart 和 flutter 的新手,我不知道该怎么做。 Can anybody help me on this?有人可以帮我吗?

Thanks谢谢

You could use fold and do something like this你可以使用fold并做这样的事情

const data = [...];

void main() {
 final value = data.fold(Map<String, List<dynamic>>(), (Map<String, List<dynamic>> a, b) {
   a.putIfAbsent(b['DateOfBirth'], () => []).add(b);
   return a;
 }).values
   .where((l) => l.isNotEmpty)
   .map((l) => {
     'DateOfBirth': l.first['DateOfBirth'],
     'BirthDay': l.first['BirthDay'],
     'Data': l.map((e) => {
       'Department': e['Department'],
       'FullName': e['FullName'],
     }).toList()
 }).toList();
}

Or like this if you want to use the spread operator, I don't know if its very readable though.或者像这样,如果你想使用扩展运算符,我不知道它是否非常可读。

 final result = data.fold({}, (a, b) => {
     ...a,
     b['DateOfBirth']: [b, ...?a[b['DateOfBirth']]],
 }).values
   .where((l) => l.isNotEmpty)
   .map((l) => {
     'DateOfBirth': l.first['DateOfBirth'],
     'BirthDay': l.first['BirthDay'],
     'Data': l.map((e) => {
       'Department': e['Department'],
       'FullName': e['FullName'],
     }).toList()
 }).toList();

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