[英]Recursive function with two inputs
Write a recursive function called print_num_pattern() to output the following number pattern.写一个递归的 function 调用 print_num_pattern() 到 output 下面的数字模式。
Given a positive integer as input (Ex: 12), subtract another positive integer (Ex: 3) continually until 0 or a negative value is reached, and then continually add the second integer until the first integer is again reached.给定一个正数 integer 作为输入(例如:12),连续减去另一个正数 integer(例如:3)直到达到 0 或负值,然后连续添加第二个 integer 直到再次达到第一个 integer。
Ex.前任。 If the input is:
如果输入是:
12 3 12 3
the output is: output 是:
12 9 6 3 0 3 6 9 12 12 9 6 3 0 3 6 9 12
Here's what I tried:这是我尝试过的:
num1 = 12
num2 = 3
def print_num_pattern(num1,num2):
if (num1 == 0 or num1 < 0):
print(num1, end = ' ')
return
print(num1, end = ' ')
print_num_pattern(num1 - num2)
print(num1, end = ' ')
print_num_pattern(num1,num2)
The most obvious error is that you're calling print_num_pattern(num1 - num2)
with only one out of two parameters最明显的错误是您调用
print_num_pattern(num1 - num2)
时只有两个参数之一
def print_num_pattern(num1,num2):
if (num1 == 0 or num1 < 0):
print(num1, end = ' ')
return
print(num1, end = ' ')
print_num_pattern(num1 - num2, num2)
print(num1, end = ' ')
It works fine after that之后它工作正常
>>> print_num_pattern(12, 3)
12 9 6 3 0 3 6 9 12
You are missing an argument in your recursive call.您在递归调用中缺少一个参数。 You need to replace this:
你需要替换这个:
print_num_pattern(num1 - num2)
with this:有了这个:
print_num_pattern(num1 - num2, num2)
import java.util.Scanner;
public class NumberPattern {
// TODO: Write recursive printNumPattern() method
static void printNumPattern(int num1, int num2){
if(num1 == -1 || num1 < 0)
{
System.out.print(num1 + " ");
return;
}
System.out.print(num1 + " ");
printNumPattern(num1 - num2, num2);
System.out.print(num1 + " " );
}
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int num1;
int num2;
num1 = scnr.nextInt();
num2 = scnr.nextInt();
printNumPattern(num1, num2);
}
}
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