如何从具有复杂结构的列表中创建 DataFrame？

Question

I have a dataframe with multiple columns (a, b, c, d). I grouped my dataframe by columns 'c' and 'd' and integrated column 'a' with respect to column 'b'. This gave me the output in the following format (the values which go like '1500, 1400... 700' are the result of the performed integration):

c d
1 10  1500
  20  1400
  30  1300
2 10  1200
  20  1100
  30  1000
3 10   900
  20   800
  30   700

I was wondering how can I convert that output into a dataframe, where it would show columns 'c', 'd', and also create a new column which would contain the result of integration?

Answer 1

Please try:

df = df.reset_index()

Answer 2

I recently created a DataFrame from similar data.

First, create simple lists for each c-value of the complex list.

c1_vals = [1500, 1400, 1300], etc

Create a DataFrame with a dictionary with c-values as keys and lists as values.

ex_df = pd.DataFrame({'1': c1_vals, '2': c2_vals, '3': c3_vals})

The d-values from the complex-data correspond to each lists' index position.

ex_df['1'][0] represents c:1 d:10

You could create variables for individual d-values like this.

c1d10 = ex_df['1'][0]