[英]How can I change the color of an image by using cv2?
Now, I got an image, and I want to change the color of it.现在,我得到了一张图片,我想改变它的颜色。 Then, show the before and after然后,显示之前和之后
This is how I write我就是这样写的
import numpy as np
import cv2
Original_img = cv2.imread('img.jpg')
New_img = Original_img
print(Original_img[0 , 20] , New_img[0 , 20])
New_img[0 , 20] = 0 #change the color of new
print( Original_img[0 , 20] , New_img[0 , 20])
But it turn out that both change.但事实证明,两者都发生了变化。 But, I only want the new one changes但是,我只想要新的改变
Output: Output:
[55 69 75] [55 69 75]
[0 0 0] [0 0 0]
This is a tricky one.这是一个棘手的问题。 It turns out that that your Original_img and New_img both refer to the same underlying object in Python.事实证明,您的 Original_img 和 New_img 都引用了 Python 中相同的底层 object。 You need to make a copy to create a new object:您需要进行复制以创建新的 object:
New_img = Original_img.copy() # use copy function from numpy
Python lists behave this way too. Python 列表的行为也是如此。 Here is a simple annotated example using a interactive Python session:这是一个使用交互式 Python session 的简单注释示例:
>>> a = [1,2,3]
>>> b = a
>>> b
[1, 2, 3]
>>> b[1] = 3.1415927 # we think we are only changing b
>>> b
[1, 3.1415927, 3] # b is changed
>>> a
[1, 3.1415927, 3] # a is also changed
Same example, using copy()
同样的例子,使用copy()
>>> from copy import copy
>>> a = [1,2,3]
>>> b = copy(a) # now we copy a
>>> b
[1, 2, 3]
>>> b[1] = 3.1415927
>>> b
[1, 3.1415927, 3] # b is changed
>>> a
[1, 2, 3] # a is unchanged!
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