列第 2 行的值复制到下一列的第 1 行

Question

The table looks like below.

DROP TABLE #TEMP
CREATE TABLE #TEMP
(
    UVRID VARCHAR(20),  
    DynamoNo INT,
    FREQHZ INT
)

INSERT #TEMP    
SELECT '15AL78',100,10 UNION ALL
SELECT '15AL78',110,20 UNION ALL
SELECT '257T13',100,10 UNION ALL
SELECT '257T13',110,20 UNION ALL
SELECT '257T13',931,30

I am trying to make 1 new column say SuprerFrez whose value is depends on column FREQHZ .

For every UVRID group 2nd value FREQHZ will be 1st value of SuprerFrez and for last FREQHZ , SuprerFrez value will be zero.

Expected output with 1 new column whose value depends upon FREQHZ column. Order by FREQHZ ASC

UVRID   |DynamoNo|FREQHZ|SuprerFrez
'15AL78'|100     |10    |20
'15AL78'|110     |20    |0
'257T13'|100     |10    |20
'257T13'|110     |20    |30
'257T13'|931     |30    |0

Answer 1

You are looking for lead() :

select t.*,
       lead(FREQhz, 1, 0) over (partition by UVRID order by DynamoNo) as SuprerFrez
from #temp t;

Note this assumes that the ordering is by DynamoNo . If that is not the ordering you have in mind, then you need another column that specifies the ordering. For instance, if you wanted "insert" order, you could use an identity column:

CREATE TABLE #TEMP (
    TempID INT IDENTITY(1, 1) PRIMARY KEY,
    UVRID VARCHAR(20),  
    DynamoNo INT,
    FREQHZ INT
);

Then the code would look like:

select t.*,
       lead(FREQhz, 1, 0) over (partition by UVRID order by TempID) as SuprerFrez
from #temp t;