Python 正则表达式：获取具有特定模式的字符串

Question

I need some help with regular expression in python. I have many files which, unfortunately, contains invaid xml: as below some 'img' tag is not closed.

<a href="a_url" class="url" target="_blank">
   <img ng-src=" {{getImageUrl('homeHelp64.jpg')}}" alt="?" width="16" height="16">
      Home
</a>

In Python what I would like to do is to find all such 'img' tags that are not closed and replace it with close tag like below ('/' before >):

<img ng-src=" {{getImageUrl('homeHelp64.jpg')}}" alt="?" width="16" height="16"/>

using the following pattern I can get all instances of img tag but i need to get only the ones that are not closed.

pattern = '(img.*?)>'

will appreciate your help in defining the pattern and how to replace the 'img' and close the xml tag at the end.

Answer 1

If I understood the problem correctly, I managed to write the required regular expression. By link, you can test the expression. Required flag - s

https://regex101.com/r/YctLzb/5/tests

\<(\w+)\s[^<>]+\>(?!.*\<\/\1\>)

Update: this works without s flag and matches tags without attrs: https://regex101.com/r/6nwHQP/1/tests

\<(\w+)(?:\s[^<>]+)?\>(?!(?:.|\n)*\<\/\1\>)