如果数组的长度大于 1，则 JSON 将 object 分离到新对象

Question

Edit: Answers don't work if there's more objects inside JSON:/ If you can take a look one more time I would be grateful.

I am trying to seperate JSON array to make new objects with single arrays.

 const objs = [{ id: ["18772729849", "17773133341", "17773173696"], o: 552750, g: 2, p: 5427.37, f: ["0.07480893", "0.07703563", "0.07160716"], b: ["76561198311594977", "76561198311424548", "76561198312084911"], d: ["uYEY1BQ", "jSdgIK5", "lldBCJt"], }, { id: ["5122519", "7125125", "124124"], o: 12440, g: 412, p: 4124, f: ["0.033", "0.0123", "0.412412"], b: ["76561198124421421", "712412441248", "71241244911"], d: ["uYasdasd1BQ", "jSasdasdK5", "llfasCJt"], } ];

And my output should look like that:

 [{ id: ['18772729849'], o: 552750, g: 2, p: 5427.37, f: ['0.07480893'], b: ['76561198311594977'], d: ['uYEY1BQ'] }, { id: ['17773133341'], o: 552750, g: 2, p: 5427.37, f: ['0.07703563'], b: ['76561198311424548'], d: ['jSdgIK5'] }, { id: ['17773173696'], o: 552750, g: 2, p: 5427.37, f: ['0.07160716'], b: ['76561198312084911'], d: ['lldBCJt5'] }, { id: ['5122519'], o: 12440, g: 412, p: 4124, f: ['0.033'], b: ['76561198124421421'], d: ['uYasdasd1BQ'] }, { id: ['7125125'], o: 12440, g: 412, p: 4124, f: ['0.0123'], b: ['712412441248'], d: ['jSasdasdK5'] },

etc

So "o", "g", "p" stays the same as in original object.

Solution:

 const objs = [{ id: ["18772729849", "17773133341", "17773173696"], o: 552750, g: 2, p: 5427.37, f: ["0.07480893", "0.07703563", "0.07160716"], b: ["76561198311594977", "76561198311424548", "76561198312084911"], d: ["uYEY1BQ", "jSdgIK5", "lldBCJt"],},{ id: ["5122519", "7125125", "124124"], o: 12440, g: 412, p: 4124, f: ["0.033", "0.0123", "0.412412"], b: ["76561198124421421", "712412441248", "71241244911"], d: ["uYasdasd1BQ", "jSasdasdK5", "llfasCJt"]}]; var result = objs.flatMap(obj=>{ return Array.from({length:obj.id.length},(_,i)=>Object.fromEntries( Object.entries(obj).map(([key, val])=>[key, Array.isArray(val)? [val[i]]: val]) )); }); console.log(result);

Answer 1

Use Object.entries and map

 const process = (arr) => { const output = []; arr.forEach((obj) => { obj.id.forEach((_, i) => { output.push( Object.fromEntries( Object.entries(obj).map(([key, value]) => [ key, Array.isArray(value)? [value[i]]: value, ]) ) ); }); }); return output; }; const objs = [ { id: ["18772729849", "17773133341", "17773173696"], o: 552750, g: 2, p: 5427.37, f: ["0.07480893", "0.07703563", "0.07160716"], b: ["76561198311594977", "76561198311424548", "76561198312084911"], d: ["uYEY1BQ", "jSdgIK5", "lldBCJt"], }, { id: ["5122519", "7125125", "124124"], o: 12440, g: 412, p: 4124, f: ["0.033", "0.0123", "0.412412"], b: ["76561198124421421", "712412441248", "71241244911"], d: ["uYasdasd1BQ", "jSasdasdK5", "llfasCJt"], }, ]; console.log(process(objs));

Answer 2

Actually just go with a .map()

 let data = { id: [ '18772729849', '17773133341', '17773173696' ], o: 552750, g: 2, p: 5427.37, f: [ '0.07480893', '0.07703563', '0.07160716' ], b: [ '76561198311594977', '76561198311424548', '76561198312084911' ], d: [ 'uYEY1BQ', 'jSdgIK5', 'lldBCJt' ] } let result = data.id.map((el,i) => { return { id: [el], o: data.o, g: data.g, p: data.p, f: [data.f[i]], b: [data.b[i]], d: [data.d[i]] } }) console.log(result);

Answer 3

You can take fromEntries of key value pair by mapping it and to generate new array you may use Array.from based on the length of the id attribute. Here is my try:

 const objs = [{ id: ["18772729849", "17773133341", "17773173696"], o: 552750, g: 2, p: 5427.37, f: ["0.07480893", "0.07703563", "0.07160716"], b: ["76561198311594977", "76561198311424548", "76561198312084911"], d: ["uYEY1BQ", "jSdgIK5", "lldBCJt"],},{ id: ["5122519", "7125125", "124124"], o: 12440, g: 412, p: 4124, f: ["0.033", "0.0123", "0.412412"], b: ["76561198124421421", "712412441248", "71241244911"], d: ["uYasdasd1BQ", "jSasdasdK5", "llfasCJt"]}]; var result = objs.flatMap(obj=>{ return Array.from({length:obj.id.length},(_,i)=>Object.fromEntries( Object.entries(obj).map(([key, val])=>[key, Array.isArray(val)? [val[i]]: val]) )); }); console.log(result);

Answer 4

You can find out the array with maximum length and then based on that generate your array of object.

 const objs = [{ id: ["18772729849", "17773133341", "17773173696"], o: 552750, g: 2, p: 5427.37, f: ["0.07480893", "0.07703563", "0.07160716"], b: ["76561198311594977", "76561198311424548", "76561198312084911"], d: ["uYEY1BQ", "jSdgIK5", "lldBCJt"], }, { id: ["5122519", "7125125", "124124"], o: 12440, g: 412, p: 4124, f: ["0.033", "0.0123", "0.412412"], b: ["76561198124421421", "712412441248", "71241244911"], d: ["uYasdasd1BQ", "jSasdasdK5", "llfasCJt"], } ], output = objs.map(o => { const length = Object.keys(o).reduce((r, k) => { if (Array.isArray(o[k])) { r = o[k].length > r? o[k].length: r; } return r; }, 0); return Array.from({ length }, (_, i) => { return Object.keys(o).reduce((r, k) => { r[k] = Array.isArray(o[k])? [o[k][i] || '']: o[k]; return r; }, {}); }); }).flat(); console.log(output);