如何使用 .bat 文件运行 jar 文件及其多个外部属性文件？

Question

I have a Maven project with three properties files under resources directory.

Existing scenario:

• At the moment, I create jar file in Eclipse through maven build with goal as "assembly:single" ensuring that the build tag in pom.xml is updated appropriately.
• This gives me a jar file with all the dependencies embedded in it.
• I execute this jar file with dependencies using batch command java -jar myjarname.jar

Desired scenario:

• However, I would like to export my project as a jar file without dependencies using "Export" feature of eclipse and place the three properties files in the same directory as where the jar file resides.

What should be the command to pass my properties files as arguments to the java -jar myname.jar ?

Answer 1

you have to prepare your program using runtime argument pass facility like below

public class Echo {
    public static void main (String[] args) {
      //  args[0] is argument1
       // args[1] is argument2
    }
}

and then update your batch file like below

java -jar myjarname.jar argument1 argument2 

you can see more example:

class A{  
public static void main(String args[]){  

for(int i=0;i<args.length;i++)  
System.out.println(args[i]);  

}  
} 

execution command:

compile by > javac A.java
run by > java A sonoo jaiswal 1 3 abc

Output: sonoo
       jaiswal
       1
       3
       abc