将列表列表转换为 python 中的唯一字典

Question

I have the following list of lists: [[100, 23], [101, 34], [102, 35]... ]

How can i convert it to a dictionary like that: {100: 23, 101: 34, 102: 35... }

Here is what i tried:

myDict = dict(map(reversed, myList))

This code works, but it will give the opposite of what i want in the dictionary: {23: 100, 101:34..}

Answer 1

You can pass a list with this format to dict() and it will convert it for you.

myList = [[100, 23], [101, 34], [102, 35]]

myDict = dict(myList)

print(myDict)

Answer 2

According to docs page for dict()

. . . the positional argument must be an iterable object. Each item in the iterable must itself be an iterable with exactly two objects. The first object of each item becomes a key in the new dictionary, and the second object the corresponding value.

and here is an example for the same doc page:

...
>>> d = dict([('two', 2), ('one', 1), ('three', 3)])

returns a dictionary equal to {"one": 1, "two": 2, "three": 3}

Answer 3

L = []
A = {}
for x,y in L:
    A[x] = y