python 将带有子列表的列表转换为字典

Question

Hello i'm new to python.

i'm working with lists in python and i want to Convert a list named graph to dictionnary graph in PYTHON .

my have list :

 graph = [ ['01 Mai', [ ['Musset', 5], ['Place 11 Decembre 1960', 4], ["Sidi M'hamed", 3], ['El Hamma (haut)', 6] ] ], ['Musset', [ ['Place 11 Decembre 1960', 4], ["Sidi M'hamed", 3], ['El Hamma (haut)', 6], ["Jardin d'Essai (haut)", 10] ], ] ]

i want the list to be a dictionary like that:

 graph = { '01 mai':{ 'Musset':5, 'Place 11 Decembre 1960':4, "Sidi M'hamed":3, "El Hamma (haut)":6, }, 'Musset':{ 'Place 11 Decembre 1960':4, "Sidi M'hamed":3, "El Hamma (haut)":6, "Jardin d'Essai (haut)": 10, } }

Answer 1

A simple dict comprehension would do:

as_dict = {k: dict(v) for k,v in graph}

Playground

Answer 2

You can use recursion to handle input of unknown depth:

graph = [['01 Mai', [['Musset', 5], ['Place 11 Decembre 1960', 4], ["Sidi M'hamed", 3], ['El Hamma (haut)', 6]]], ['Musset', [['Place 11 Decembre 1960', 4], ["Sidi M'hamed", 3], ['El Hamma (haut)', 6], ["Jardin d'Essai (haut)", 10]]]]
def to_dict(d):
  return {a:b if not isinstance(b, list) else to_dict(b) for a, b in d}

print(to_dict(graph))

Output:

{'01 Mai': {'Musset': 5, 'Place 11 Decembre 1960': 4, "Sidi M'hamed": 3, 'El Hamma (haut)': 6}, 'Musset': {'Place 11 Decembre 1960': 4, "Sidi M'hamed": 3, 'El Hamma (haut)': 6, "Jardin d'Essai (haut)": 10}}

Answer 3

An easy solution would be:

for item in graph:
    d[item[0]] = {record[0]: record[1] for record in item[1]}