如何从 python 中的以下元组中获取 IP 地址

Question

('table',
 [(1,
   {u'Node': u'1',
    u'Mode': u'a',
    u'HostName': u'hn19',
    u'Address': u'10.10.10.10'}),
   (2,
    {u'Node': u'2',
     u'Mode': u'b',
     u'HostName': u'hn20',
     u'Address': u'10.10.10.11'})]) 

Please suggest some ways to avoid loops. thanks in advance:)

Answer 1

_, table = that_data_you_posted
ip_addresses = [d[u'Address'] for _, d in table]

This just hides the loop in a list comprehension. There's obviously no way to avoid iterating over multiple rows in a table.

Answer 2

Since this is a small tuple, we can continue with using index, but when you have a larger tuple, you'll surely have to use loops.

For now you may try this

#a is your tuple.
ipaddress1 = a[1][0][1][u'Address']
ipaddress2 = a[1][1][1][u'Address'] 

I hope this helped.

Answer 3

i would have created dict of key as host, values ip.

_, lst = tpl
ip_dict= { d[u'hn20'] : d[u'Address'] for _,d if u'hn20' in d and u'Address' in d }

the if condition is important because there are possibilities this key missing in dict.