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如何从python中的命名元组获取名称?

[英]How do I get the name from a named tuple in python?

I create a named tuple like this: 我创建一个这样的命名元组:

from collections import namedtuple
spam = namedtuple('eggs', 'x, y, z')
ham = spam(1,2,3)

Then I can access elements of ham with eg 然后我可以用例如火腿访问元素

>>> ham.x
1
>>> ham.z
3

In the interpreter, 在翻译中,

>>> ham
eggs(x=1, y=2, z=3)

But what if I just want to get 'eggs'? 但是,如果我只想得到“蛋”呢? The only way I've been able to think of is 我能想到的唯一方法是

>>> ham.__repr__.split('(')[0]
'eggs'

but this seems a bit messy. 但这似乎有点凌乱。 Is there a cleaner way of doing it? 这样做有更清洁的方法吗?

Why do named tuples have this 'eggs' aspect to them if it isn't possible to access it without resorting to a private method? 如果不使用私有方法无法访问它,为什么命名元组有这种“蛋”方面?

You can get the __name__ attribute of the class: 您可以获取__name__属性:

>>> type(ham).__name__
'eggs'

(Here using the type() builtin to get the class). (这里使用内置的type()来获取类)。

On the topic of namedtuple attributes: 关于namedtuple属性的主题:

 >>> ham._fields
    ('x', 'y', 'z')

is sometimes useful to know 知道有时很有用

>>> ham.__class__.__name__
'eggs'

Based on python's doc , namedtuple gives you a new tuple subclass named 'eggs' 基于python的docnamedtuple为你提供了一个名为'eggs'的namedtuple组子类

So essentially you need the class name 所以基本上你需要类名

and type(ham).__name__ will give you the class name type(ham).__name__将为您提供类名

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