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如何编写将被继承的通用代码?

[英]How can I write generic code that will be inherited?

I'm trying to write some generic code in a parent class that gets inherited.我正在尝试在继承的父 class 中编写一些通用代码。 However, I'm struggling with the type-ing of some of the variables.但是,我正在努力输入一些变量。 Take the code below:拿下面的代码:

class A {
    protected:
        std::vector<void*> struct1;
        std::vector<void*> struct2;
        std::vector<void*> struct3;
    public:
    A::~A()
    {
        for(decltype(A::struct1)* i : A::struct1) {
            free(i);
        }
        for(decltype(A::struct2)* i : A::struct2) {
            free(i);
        }
        for(decltype(A::struct3)* i : A::struct3) {
            free(i);
        }
    }
}

class B {
    protected:
        std::vector<b*> struct1;
        std::vector<b*> struct2;
        std::vector<b*> struct3;
}

class C {
    protected:
        std::vector<c*> struct1;
        std::vector<c*> struct2;
        std::vector<c*> struct3;
}

(where b and c are structs). (其中bc是结构)。

I'm getting issues with the iterator ( a value of type "void *" cannot be used to initialize an entity of type "std::vector<void *, std::allocator<void *>> *" ), which makes sense.我遇到了迭代器的问题( a value of type "void *" cannot be used to initialize an entity of type "std::vector<void *, std::allocator<void *>> *" ),这使得感觉。 But class A will never be directly used, only B and C, so A won't run into that issue ever because the structs will have proper types.但是 class 永远不会直接使用 A,只有 B 和 C,所以 A 永远不会遇到这个问题,因为结构将具有正确的类型。

Did you mean that you wanted classes like B to inherit from A so that the destructor will destroy the contents of the vector s?您的意思是您希望像B这样的类从A继承,以便析构函数破坏vector s 的内容吗?

template<typename T>
class A {
protected:
    std::vector<T*> struct1;
    std::vector<T*> struct2;
    std::vector<T*> struct3;
public:
    A::~A() {
        for(auto i : struct1) {
            delete i;
        }
        for(auto i : struct2) {
            delete i;
        }
        for(auto i : struct3) {
            delete i;
        }
    }
}

class B: public A<B> {
}

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