我如何删除包含日期时间非连续的行（数据框）

Question

I want to create a function that takes dataframe as input and returns it after doing these operations:

1. Count the number of rows that if we compare it with rows before it and after it we get consecutive date.

2. Drop all the rows that do not fulfill the condition above

The dataframe:

Answer 1

For your question you can use date_range function. You can use it like this

import pandas as pd
range=pd.date_range('START DATE','END DATE',freq='1D')
df = pd.DataFrame({'a': range(NO OF PERIODS)}, index=range)  
print (df) 

This will give you all the dates which are continuous as daily, starting from that date. And you can use these continuous dates as your index. Thus rows not fulfilling your wish will be skipped.

For detailed knowledge of date_range you can refer enter link description here