Malloc 动态数组大小导致分段错误

Question

My goal is to have a an array of arrays so I can get the size from another variable and append as many objects as I need in a for loop later.

Sorta like this:

char *test[3][1][3] = {
    {"FOO", "BAR"},
    {"BIZ", "NIZ"},
    {"BIZ", "NIZ", "NAZ"}
};

    
printf("\nTESTNG: \n");
printf("TEST: %s\n", test[0][0][0]);
printf("TEST: %s\n", test[0][0][1]);

// this is the only value that is dynamic, the rest are key value pairs that are being inserted
// like FOO : BAR
// this function returns an integer
int array_size = someotherfunction();

char** people = (char**) malloc(array_size);
for(i = 0; i < array_size; i++){
        people[i] = (char*)malloc(2);
}
people[0][0][0] = "FOO";
printf("Person: %s", people[0][0][0]);

Answer 1

Right now you have 4D char array. The following code is sufficient for your data.There is no point of extra dimension if size of that dimension is one.

    char *test[3][3] = {
        {"FOO", "BAR"},
        {"BIZ", "NIZ"},
        {"BIZ", "NIZ", "NAZ"}
    };
printf("TEST: %s\n", test[0][0]);
printf("TEST: %s\n", test[0][1]);

Edited:

Following is for char* test[NumElement] . Similarly you can implement for 3d array.

char **test = malloc(sizeof(char*) * NumElement);
for (i = 0; i < NumElement; i++)
{
    test[i] = malloc((STR_Length+1)* sizeof(char));  //for "FOO" STR_Length is 3, +1 for null char
}

Edited2: exact code

int N = 3, M = 3, STRLEN=3;
char *** test = (char *** )malloc(N * sizeof(char ** )) ;  //equal to char * test[N][M]
for(int i = 0 ; i < N ; i++ ) //Allocate memroy for each row
{ 
    test[i] = (char ** ) malloc(M * sizeof(char * )) ;
    for ( int j = 0 ; j < M ; j++ )
    { 
        test[i][j] = (char *) malloc ((STRLEN+1) * sizeof(char));
    }
 }
 test[0][0] = "FOO";
 test[0][1] = "BAR" ;
 printf("%s\n",test[0][0]);
 printf("%s\n",test[0][1]);