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在 arrays 的数组中添加数字

[英]Adding numbers inside array of arrays

Here I'm trying to add number of array separately, but I'm not able to achieve the expected output.在这里,我尝试单独添加数组数量,但无法达到预期的 output。 If I want to add total I would do flatMap and add them togeather.如果我想加总,我会做flatMap并将它们加在一起。 But I want add them separately for each array.但我想为每个数组分别添加它们。

Below is the snippet for what I have tried以下是我尝试过的片段

 const data = [{ "itemDetails": [{ "sizeOfBag": 1, "numberOfBags": 1, "quantityInBag": 1.0 }] }, { "itemDetails": [{ "sizeOfBag": 1, "numberOfBags": 1, "quantityInBag": 1.0 }, { "sizeOfBag": 10, "numberOfBags": 1, "quantityInBag": 1.0 } ], } ] const newData = data.map(f => f.itemDetails); console.log(newData); for (let i = 0; i <= newData.length; i++) { const addData = newData.reduce((acc, newData) => acc + newData[i].sizeOfBag, 0); } console.log(addData);

Expected Output: [1,11]预期 Output: [1,11]

You can use map and reduce.您可以使用 map 并减少。

const res = newData.map(arr=>arr.reduce((acc,curr)=>acc+curr.sizeOfBag,0));

Your attempt with the for loop is close, but you are looping past the last index and mixing up your index with property names.您对 for 循环的尝试很接近,但是您正在循环过去最后一个索引并将索引与属性名称混合在一起。

for (let i = 0; i < newData.length; i++) {
  newData[i] = newData[i].reduce((acc, newData) => acc + newData.sizeOfBag, 0);
}

You need to call reduce on the nested arrays, not the top-level newData array.您需要在嵌套的 arrays 上调用reduce ,而不是顶级newData数组。 You can combine all these calls using map to get an array of the results.您可以使用map组合所有这些调用以获得结果数组。

 const data = [{ "itemDetails": [{ "sizeOfBag": 1, "numberOfBags": 1, "quantityInBag": 1.0 }] }, { "itemDetails": [{ "sizeOfBag": 1, "numberOfBags": 1, "quantityInBag": 1.0 }, { "sizeOfBag": 10, "numberOfBags": 1, "quantityInBag": 1.0 } ], } ] const newData = data.map(f => f.itemDetails); console.log(newData); const addData = newData.map(d => d.reduce((acc, x) => acc + x.sizeOfBag, 0)); console.log(addData);

Do it like this, run the reduce function inside your map:这样做,在 map 中运行 reduce function:

data.map(f => f.itemDetails.reduce((acc, i) => acc + i.sizeOfBag, 0));

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