[英]Calling a function with its previous return value as an argument in a while loop in Python
I need to keep calling the following function with its previous return value as an argument in a while loop:我需要继续调用以下 function 及其先前的返回值作为 while 循环中的参数:
def announce_lead_changes(last_leader=None):
"""Return a commentary function that announces lead changes.
>>> f0 = announce_lead_changes()
>>> f1 = f0(5, 0)
Player 0 takes the lead by 5
>>> f2 = f1(5, 12)
Player 1 takes the lead by 7
>>> f3 = f2(8, 12)
>>> f4 = f3(8, 13)
>>> f5 = f4(15, 13)
Player 0 takes the lead by 2
"""
def say(score0, score1):
if score0 > score1:
leader = 0
elif score1 > score0:
leader = 1
else:
leader = None
if leader != None and leader != last_leader:
print('Player', leader, 'takes the lead by', abs(score0 - score1))
return announce_lead_changes(leader)
return say
I understand how the doctest works but how do I implement this in a while loop?我了解 doctest 的工作原理,但是如何在 while 循环中实现它? I tried the following but it keeps on passing the default argument throughout loop:我尝试了以下方法,但它继续在整个循环中传递默认参数:
commentary = both(say_scores, announce_lead_changes())
while
...
commentary(score0, score1)
Update commentary
for each iteration in the while loop.更新 while 循环中每次迭代的commentary
。 Try:尝试:
commentary = both(say_scores, announce_lead_changes())
while
...
commentary = commentary(score0, score1)
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